Mathematics Assignment
Assuming that this is an assignment you'll more than likely need written responses. Here's what you could write for Q1:
Upon investigation for how to work out the last two digit numbers in the result of 91^92, i first recognised when multiplying 91 continuous times I would get the following results:
91 x 91 = 8281 ;^2
8281 x 91 = 753571 ;^3
753571 x 91 = 68574961 ;^4
Upon these results it can be safe to say that the final number will always result in 1, and that the second digit will continue to decrease at the rate of -1 every time the following number is multiplied by 91. Further investigation also proved that when the second to last number reached 0 it would return to 9 when multiplied again, as shown:
38941611811810745401 x 91 = 3543686674874777831491
I also noticed that the second to last number would appear every time 91 was multiplied by itself for the 10th consecutive time.
For example 12th time = 8, 22nd time = 8 etc
Therefore continuing with these findings it can be assumed that for the result of 91^92 the final two digits will be 8 and 1.
You may want to change this a bit depending on how you yourself want to respond to the question. But for what its worth I've confirmed it myself and this IS the correct answer.
I hope this helps you and I'm sorry that I can't help with the remaining questions :( but 2 and 3 certainly sound like you are required to use a combination of some sort
Good Luck with your assignment :)
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